Physics Formulas – Proton, Electron, Mass & Energy Relations

 

1️⃣ Proton Energy – Mass Relation (Pythagoras Style)

                       Sree Debasish Dasgupta

• Proton Energy (iA):

iA=a2+b22×2×(4root>4π)iA = \sqrt{\frac{a^2 + b^2}{2}} \times 2 \times (4\text{root} > 4\pi)iA=2a2+b2​​×2×(4root>4π)

• Proton Mass via Energy:

Proton Mass=[(a2+b2)/(X/Y)]2a+b×iA\text{Proton Mass} = \frac{[(a^2 + b^2) / (X/Y)]^2}{a+b} \times iAProton Mass=a+b[(a2+b2)/(X/Y)]2​×iA

• Rule for Energy:

Energy={[4root>4π]×2}×Energy2×Proton Energy\text{Energy} = \{[4\text{root} > 4\pi] \times 2\} \times \sqrt{\frac{\text{Energy}}{2}} \times \text{Proton Energy}Energy={[4root>4π]×2}×2Energy​​×Proton Energy

• Rule for Mass:

Mass={[4root>4π]×2}×Energy2×Proton Mass\text{Mass} = \{[4\text{root} > 4\pi] \times 2\} \times \sqrt{\frac{\text{Energy}}{2}} \times \text{Proton Mass}Mass={[4root>4π]×2}×2Energy​​×Proton Mass

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2️⃣ Root 3 Cube – Time – Mass Relation

• Cube of Root 3 multiplied by 4:

X=(3)3×4X = (\sqrt{3})^3 \times 4X=(3​)3×4

• Time Ratios:

X/Y=432/3600=0.12,Y/X=3600/432=8.3333X/Y = 432 / 3600 = 0.12, \quad Y/X = 3600 / 432 = 8.3333X/Y=432/3600=0.12,Y/X=3600/432=8.3333

• Mass Calculation using Energy & Time:

(CX/Y)2=Mass,[C×(Y/X)]2=Mass\left(\frac{C}{X/Y}\right)^2 = \text{Mass}, \quad [C \times (Y/X)]^2 = \text{Mass}(X/YC​)2=Mass,[C×(Y/X)]2=Mass

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3️⃣ Electron Mass & Energy Distribution in 360° Orbit

• Unit Energy per Degree:

1∘Energy=1.60217653×10−19360=4.45049×10−22 Unit1^\circ \text{Energy} = \frac{1.60217653 \times 10^{-19}}{360} = 4.45049 \times 10^{-22} \, \text{Unit}1∘Energy=3601.60217653×10−19​=4.45049×10−22Unit

• Energy per Electron (Minimum 11.25° Angle):

Eelectron=11.25×4.45049×10−22=5.0068×10−21 UnitE_{\text{electron}} = 11.25 \times 4.45049 \times 10^{-22} = 5.0068 \times 10^{-21} \, \text{Unit}Eelectron​=11.25×4.45049×10−22=5.0068×10−21Unit

• Time per Degree:

T1∘=3600/360=10 sec,Electron Induction Time=3.75∘×10×3=112.5 secT_{1^\circ} = 3600/360 = 10 \, \text{sec}, \quad \text{Electron Induction Time} = 3.75^\circ \times 10 \times 3 = 112.5 \, \text{sec}T1∘​=3600/360=10sec,Electron Induction Time=3.75∘×10×3=112.5sec

• Energy-Time Interaction:

E×T×(0.5333)2=1.60217653×10−19 Unit EnergyE \times T \times (0.5333)^2 = 1.60217653 \times 10^{-19} \, \text{Unit Energy}E×T×(0.5333)2=1.60217653×10−19Unit Energy

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4️⃣ Mass–Energy Conversion Formula

• Fundamental Rule:

E=m−m10E = m - \frac{m}{10}E=m−10m​

• Digit-Based Mass Relation:

m×109≈1.78262 Unit Massm \times \frac{10}{9} \approx 1.78262 \, \text{Unit Mass}m×910​≈1.78262Unit Mass

• Small Unit Mass:

1.78262/1036=1.78262×10−36 Unit Mass1.78262 / 10^{36} = 1.78262 \times 10^{-36} \, \text{Unit Mass}1.78262/1036=1.78262×10−36Unit Mass

• Useful Conversion:

1.60436×10−39×16→1.60217653×10−19 Unit Energy1.60436 \times 10^{-39} \times 16 \rightarrow 1.60217653 \times 10^{-19} \, \text{Unit Energy}1.60436×10−39×16→1.60217653×10−19Unit Energy

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5️⃣ Proton & Electron Mass via Interaction Chains

• Proton Mass via Interaction:

Proton Mass×iA=1.782662×10−36 Unit Mass\text{Proton Mass} \times iA = 1.782662 \times 10^{-36} \, \text{Unit Mass}Proton Mass×iA=1.782662×10−36Unit Mass

• Electron–Neutron Mass Relation:

mNeutron=9.11214×10−31×1838=1.67481×10−27 Unitm_{\text{Neutron}} = 9.11214 \times 10^{-31} \times 1838 = 1.67481 \times 10^{-27} \, \text{Unit}mNeutron​=9.11214×10−31×1838=1.67481×10−27Unit

• Mass Calculation Using Energy-Time:

Mass=[C/(X/Y)]2or[C×(Y/X)]2\text{Mass} = [C / (X/Y)]^2 \quad \text{or} \quad [C \times (Y/X)]^2Mass=[C/(X/Y)]2or[C×(Y/X)]2