My request to all
student societies is to read my 'Atomic Philosophy in the Path of Light ' essay carefully. This article contains some information that will be
useful for you in the future. Mendeley's data has been published, it can be found if you search Google. Link;
https://data.mendeley.com/datasets/st6fxh2mnb/1
Below are some examples.
·
Crucial Number in
Particle Creation: The number '0.413334' appears to play a vital role in the creation
of various particles and elements, suggesting that there may be a foundational
ratio or constant that governs their formation.
Visible Light Energy and Frequency
Relationship: The relationship between energy (eV) and frequency is articulated
in the equation eV = 0.413334 x Frequency, suggesting a direct correlation
between these two physical properties.
For Example:- Understanding the use of
‘Electron Volt = Frequency x 0.413334’ formula as unit conversions in
current units calculation.
Question : (Example) - Electro light action of starting wave
length is 7000 Angstrom to any metal transform it to the unit of W0 to eV .
(h=6.60 x 10^-27 erg-s , eV = 1.6 x 10^-12
erg)
Solve : -
We know
Frequency = speed of light / wave length
So here
frequency : = 4.2857 x 10^14 Hz .
As per my
rule (without any power) eV = frequency x 0.413334
eV = (4.2857
x 0.413334) = 1.7714 unit (eV)
and same way frequency = eV / 0.413334
Frequency =
(1.7714 / 0.413334) = 4.2857 unit (Current unit Hertz)
·
Pi and Particle
Masses: The constant Pi can be expressed through a complex formula that
integrates the mass values of electrons and protons, illustrating a deep
interconnection between these fundamental constants and the energies involved.
Pi = {[( root over electron either protons
mass value energy) / (Proton energy as per e =mc2)] / 2 }^4
For Example:-
[We know that one (Pi =
3.1415926535897932384626433832795 and as per “e=mc^2
.” 1.5032784196545335010226279575152e-10 Unit = Proton’s
mass equivalent energy.
And 1.60217653e-19 Unit electric charge of a Proton then
(-1.60217653e-19) Unit electric charge of
an electron]
Now, 1.60217653e-19
Root over> = 4.0027197378782342122581519961685e-10
4.0027197378782342122581519961685e-10 /
1.5032784196545335010226279575152e-10 = 2.6626602800551704435263034591073 /2 =
(1.3313301400275852217631517295536)
(1.3313301400275852217631517295536)^4 = 3.1415433470961018845922239897721 =[Pi].
Next.
( 1.60217653e-19 / 2) = 8.01088265e-20
root>
8.01088265e-20 = 2.8303502698429394217655138448226e-10
(2.8303502698429394217655138448226e-10 /
1.5032784196545335010226279575152e-10) = 1.882785140023082758292977718897
1.882785140023082758292977718897^4
=12.566173388384407538368895959089 = 4Pi
So, {[Root over (protons electric
charge/2)]/ (Proton energy as per e =mc2)]}^4
=4Pi,
·
Proton Mass
Calculation: The mass of a proton can be derived from the electron mass using a
specific formula involving the number 0.413334, thus establishing a calculative
approach to understanding the mass ratio between these particles.
[(Electron mass) / ( 0.413334 x 10 )^2 ] x (Pi)^9 x [(Pi) / 3 ]
= PROTON’s MASS
Pi and Particle Masses: The constant Pi
can be expressed through a complex formula that integrates the mass values of
electrons and protons, illustrating a deep interconnection between these
fundamental constants and the energies involved.
[ (Electron mass) /
(0.413334 *10) ^2 ] divided by (Pi)^9 = Mass. 1.782662e-36 unit.
Or, 1/ {(Pi)^9 / [(Electron mass) / (0.413334 *10)^2]
} = Mass, 1.782662e-36
unit.
For Example:- Investigating the impact of internal changes on the properties of
particles and exploring the role of (L
= 0.413334) and (Pi), in electron, protons mass and energy.
We know that , as per (e=mc^2) equation. (Mass = 1.782662e-36 Kg. When energy = 1.60217653e-19
Joule.
Electron mass = 9.109390e-31kg, C^2 = speed of light square)
‘L’ = (photon’s eV 1.24 unit / 3) = 0.413334,
(0.413334
x10) ^2 = 17.084449955556
, either [L x (Time /space)] = [0.413334 x (3600/360)]^2
=17.084449955556 [3600 second & 360 Degree ]
(9.109390e-31/17.084449955556) =
5.3319773382798041975309487724255e-32
(Electron
mass) / (0.413334 *10) ^2 = 5.3319773382798041975309487724255e-32 ---- (1a)
[1.2985270578788836 is constant unit for
particle energy, and ‘L’ = 0.413334, in this article, this subject has been
discussed earlier]
22/7 =
(3.1428571428571428571428571428571) = Pi
(3.1428571428571428571428571428571)^9
= 2.9917256660402129603928590571842e+4 ---(2a)
Next
Equation, (2a /
1a) =
(2.9917256660402129603928590571842e+4
/ 5.3319773382798041975309487724255e-32)
=
5.6109121930465663243853382177961e+35
(1/5.6109121930465663243853382177961e+35) = 1.7822414e-36 Unit Mass.
As per (e=mc^2) equation. (Mass = 1.782662e-36 Kg. When energy = 1.60217653e-19
J. )
Either — (1a)/(2a) =
(5.3319773382798041975309487724255e-32
/ 2.9917256660402129603928590571842e+4)
. =
1.7822414e-36 Unit mass.
So [
(Electron mass) / (0.413334 *10) ^2 ] divided by (Pi)^9 =
Mass.
Or, 1/
{(Pi)^9 / [(Electron
mass) / (0.413334 *10)^2] } = Mass,
[As per (e=mc^2) equation. Mass = 1.782662e-36 Unit. When energy = 1.60217653e-19
Unit ]
Next , (1a)x(2a).=
(5.3319773382798041975309487724255e-32)
x (2.9917256660402129603928590571842e+4)
=
1.5951813453676469100727741096844e-27.
(1.5951813453676469100727741096844e-27) *
(3.1428571428571428571428571428571 /3)
=
1.6711423618137253343619538291932e-27 Unit.
Proton’s mass.
So, (1a)x(2a) x [(22/7) / 3 ]
or,
[(Electron mass) / ( 0.413334 x 10 )^2 ] x (Pi)^9 x [(Pi) / 3 ]
= PROTON’s MASS.
We know
that, as per (e=mc^2)
equation. Proton’s mass = 1.672623e-27 Kg.
Overall, these points underscore the intricate relationships and
constants that define the behavior and characteristics of fundamental particles
and the energies associated with them. They present a framework for further
exploration and understanding of the principles governing atomic and subatomic
phenomena.
