Physics Formulas – Proton, Electron, Mass & Energy Relations [II]

 

1. Proton Energy – Mass Relation (Pythagoras Style -II)

a2+b22×2×(4root>4π)=iA\sqrt{\frac{a^2 + b^2}{2}} \times 2 \times (4\text{root} > 4\pi) = iA2a2+b2​​×2×(4root>4π)=iA [(a2+b2)/(X/Y)]2a+b=Mass / Energy\frac{[(a^2 + b^2) / (X/Y)]^2}{a+b} = \text{Mass / Energy}a+b[(a2+b2)/(X/Y)]2​=Mass / Energy (iA)×Proton Mass=Mass(iA) \times \text{Proton Mass} = \text{Mass}(iA)×Proton Mass=Mass Rule 4: {[4root>4π]×2}×Energy2×Proton Energy=Energy\text{Rule 4: } \{[4\text{root} > 4\pi] \times 2\} \times \sqrt{\frac{\text{Energy}}{2}} \times \text{Proton Energy} = \text{Energy}Rule 4: {[4root>4π]×2}×2Energy​​×Proton Energy=Energy Rule 5: {[4root>4π]×2}×Energy2×Proton Mass=Mass\text{Rule 5: } \{[4\text{root} > 4\pi] \times 2\} \times \sqrt{\frac{\text{Energy}}{2}} \times \text{Proton Mass} = \text{Mass}Rule 5: {[4root>4π]×2}×2Energy​​×Proton Mass=Mass

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2. Root 3 Cube – Time – Mass Relation

X=(Root 3)3×4X = (\text{Root 3})^3 \times 4X=(Root 3)3×4 X/Y=432/3600=0.12,Y/X=3600/432=8.3333X / Y = 432 / 3600 = 0.12, \quad Y / X = 3600 / 432 = 8.3333X/Y=432/3600=0.12,Y/X=3600/432=8.3333 (CX/Y)2=Mass,[C×(Y/X)]2=Mass\left(\frac{C}{X/Y}\right)^2 = \text{Mass}, \quad [C \times (Y/X)]^2 = \text{Mass}(X/YC​)2=Mass,[C×(Y/X)]2=Mass Energy×(Y/X)=Energy in Mass Units\text{Energy} \times (Y/X) = \text{Energy in Mass Units}Energy×(Y/X)=Energy in Mass Units

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3. Electron Mass & Energy Distribution (360°)

1° Energy=1.60217653×10−19360=4.4504903611×10−22 Unit\text{1° Energy} = \frac{1.60217653 \times 10^{-19}}{360} = 4.4504903611 \times 10^{-22} \, \text{Unit}1° Energy=3601.60217653×10−19​=4.4504903611×10−22Unit Energy per electron (11.25°)=11.25×4.4504903611×10−22=5.0068×10−21 Unit\text{Energy per electron (11.25°)} = 11.25 \times 4.4504903611 \times 10^{-22} = 5.0068 \times 10^{-21} \, \text{Unit}Energy per electron (11.25°)=11.25×4.4504903611×10−22=5.0068×10−21Unit Time per 1°=3600360=10 sec,3.75°=37.5 sec, with induction area 37.5×3=112.5 sec\text{Time per 1°} = \frac{3600}{360} = 10 \, \text{sec}, \quad 3.75 \text{°} = 37.5 \text{ sec}, \text{ with induction area } 37.5 \times 3 = 112.5 \text{ sec}Time per 1°=3603600​=10sec,3.75°=37.5 sec, with induction area 37.5×3=112.5 sec [1S]×[2S]×(0.5333)2=1.60217653×10−19 Unit Energy[1S] \times [2S] \times (0.5333)^2 = 1.60217653 \times 10^{-19} \, \text{Unit Energy}[1S]×[2S]×(0.5333)2=1.60217653×10−19Unit Energy

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4. Mass–Energy Conversion (E = m – m/10)

E=m−m10E = m - \frac{m}{10} E=m−10m​ Example: 1.6043560208×10−39×16→Energy=1.60217653×10−19 Unit\text{Example: } 1.6043560208 \times 10^{-39} \times 16 \rightarrow \text{Energy} = 1.60217653 \times 10^{-19} \, \text{Unit}Example: 1.6043560208×10−39×16→Energy=1.60217653×10−19Unit Digit Check: 1.6043560208×109=1.7826178009 Mass Unit\text{Digit Check: } 1.6043560208 \times \frac{10}{9} = 1.7826178009 \, \text{Mass Unit}Digit Check: 1.6043560208×910​=1.7826178009Mass Unit Mass Unit 1.7826178009/1036=1.7826178009×10−36 Mass Unit\text{Mass Unit } 1.7826178009 / 10^{36} = 1.7826178009 \times 10^{-36} \, \text{Mass Unit}Mass Unit 1.7826178009/1036=1.7826178009×10−36Mass Unit

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5. Proton & Electron Mass via Interaction Chains

Proton Mass×iA=1.782662×10−36 Unit\text{Proton Mass} \times iA = 1.782662 \times 10^{-36} \, \text{Unit}Proton Mass×iA=1.782662×10−36Unit Electron Mass Relation: 9.11214×10−31×1838=1.67481×10−27 Neutron Mass\text{Electron Mass Relation: } 9.11214 \times 10^{-31} \times 1838 = 1.67481 \times 10^{-27} \, \text{Neutron Mass}Electron Mass Relation: 9.11214×10−31×1838=1.67481×10−27Neutron Mass Energy / (X/Y)2=Mass,[C×(Y/X)]2=Mass\text{Energy / (X/Y)}^2 = \text{Mass}, \quad [C \times (Y/X)]^2 = \text{Mass}Energy / (X/Y)2=Mass,[C×(Y/X)]2=Mass