Thursday, 26 September 2024

My request to all student societies

 

My request to all student societies is to read my  'Atomic Philosophy in the Path of Light ' essay carefully. This article contains some information that will be useful for you in the future. Mendeley's data has been published, it can be found if you search Google. Link; https://data.mendeley.com/datasets/st6fxh2mnb/1

 Below are some examples.

·         Crucial Number in Particle Creation: The number '0.413334' appears to play a vital role in the creation of various particles and elements, suggesting that there may be a foundational ratio or constant that governs their formation.

Visible Light Energy and Frequency Relationship: The relationship between energy (eV) and frequency is articulated in the equation eV = 0.413334 x Frequency, suggesting a direct correlation between these two physical properties.

For Example:- Understanding the use of   ‘Electron Volt = Frequency x 0.413334’ formula as unit conversions in current units calculation. 

 

Question : (Example)  - Electro light action of starting wave length is 7000 Angstrom   to any metal transform it to the unit of W0  to eV .

(h=6.60 x 10^-27 erg-s , eV = 1.6 x 10^-12 erg)

Solve : -

We know  Frequency = speed of light / wave length

 So here frequency : = 4.2857 x 10^14 Hz .

 As per my rule (without any power) eV = frequency x 0.413334

eV = (4.2857  x 0.413334) = 1.7714 unit (eV)

and same way frequency = eV /  0.413334

 Frequency = (1.7714 / 0.413334) = 4.2857 unit (Current unit Hertz)

 

·         Pi and Particle Masses: The constant Pi can be expressed through a complex formula that integrates the mass values ​​of electrons and protons, illustrating a deep interconnection between these fundamental constants and the energies involved.

 Pi = {[( root over electron either protons mass value energy) / (Proton energy as per e =mc2)] / 2 }^4

For Example:-

[We know that one (Pi  = 3.1415926535897932384626433832795 and  as per “e=mc^2 .” 1.5032784196545335010226279575152e-10 Unit = Proton’s mass equivalent energy.

And 1.60217653e-19 Unit electric charge of a Proton then (-1.60217653e-19) Unit electric charge of an electron] 

Now, 1.60217653e-19

Root over> = 4.0027197378782342122581519961685e-10

4.0027197378782342122581519961685e-10 / 1.5032784196545335010226279575152e-10 = 2.6626602800551704435263034591073 /2 = (1.3313301400275852217631517295536)

(1.3313301400275852217631517295536)^4 = 3.1415433470961018845922239897721 =[Pi].

 

Next.

( 1.60217653e-19 / 2) = 8.01088265e-20

 root> 8.01088265e-20 = 2.8303502698429394217655138448226e-10

(2.8303502698429394217655138448226e-10 / 1.5032784196545335010226279575152e-10) = 1.882785140023082758292977718897

1.882785140023082758292977718897^4 =12.566173388384407538368895959089 = 4Pi

So,  {[Root over (protons  electric  charge/2)]/ (Proton energy as per e =mc2)]}^4 =4Pi,

 

·         Proton Mass Calculation: The mass of a proton can be derived from the electron mass using a specific formula involving the number 0.413334, thus establishing a calculative approach to understanding the mass ratio between these particles.

[(Electron mass) / ( 0.413334 x 10 )^2  ] x (Pi)^9 x  [(Pi) / 3 ]  = PROTON’s MASS  

 

Pi and Particle Masses: The constant Pi can be expressed through a complex formula that integrates the mass values ​​of electrons and protons, illustrating a deep interconnection between these fundamental constants and the energies involved.

 [ (Electron mass) / (0.413334 *10) ^2 ] divided by (Pi)^9 = Mass. 1.782662e-36 unit.

Or, 1/ {(Pi)^9 / [(Electron mass) / (0.413334 *10)^2] } = Mass, 1.782662e-36 unit.

 

For Example:-  Investigating the impact of  internal changes on the properties of particles and exploring the role of   (L = 0.413334) and (Pi), in electron, protons mass and energy.

We know that , as per (e=mc^2) equation. (Mass = 1.782662e-36 Kg.  When energy = 1.60217653e-19 Joule.

Electron mass = 9.109390e-31kg, C^2 = speed of light square)

 

 ‘L’ = (photon’s eV 1.24 unit / 3) = 0.413334,

(0.413334 x10) ^2 = 17.084449955556 , either [L x (Time /space)] = [0.413334 x (3600/360)]^2 =17.084449955556 [3600 second & 360 Degree ]

(9.109390e-31/17.084449955556) = 5.3319773382798041975309487724255e-32

(Electron mass) / (0.413334 *10) ^2 = 5.3319773382798041975309487724255e-32 ---- (1a)

 [1.2985270578788836 is constant unit for particle energy, and ‘L’ = 0.413334, in this article, this subject has been discussed earlier]

22/7 = (3.1428571428571428571428571428571) = Pi

(3.1428571428571428571428571428571)^9 = 2.9917256660402129603928590571842e+4 ---(2a)

 

 

Next

Equation,  (2a / 1a) =

(2.9917256660402129603928590571842e+4 / 5.3319773382798041975309487724255e-32)

= 5.6109121930465663243853382177961e+35 

(1/5.6109121930465663243853382177961e+35)  = 1.7822414e-36 Unit Mass.

As per (e=mc^2) equation. (Mass = 1.782662e-36 Kg.  When energy = 1.60217653e-19 J. ) 

Either — (1a)/(2a) =

(5.3319773382798041975309487724255e-32 / 2.9917256660402129603928590571842e+4)

. = 1.7822414e-36 Unit mass.

So [ (Electron mass) / (0.413334 *10) ^2 ] divided by (Pi)^9 = Mass. 

Or, 1/ {(Pi)^9 / [(Electron mass) / (0.413334 *10)^2] } = Mass,   

[As per (e=mc^2) equation. Mass = 1.782662e-36 Unit.  When energy = 1.60217653e-19 Unit ]

 

Next , (1a)x(2a).= 

(5.3319773382798041975309487724255e-32) x (2.9917256660402129603928590571842e+4)

= 1.5951813453676469100727741096844e-27.

 (1.5951813453676469100727741096844e-27) * (3.1428571428571428571428571428571 /3)

= 1.6711423618137253343619538291932e-27 Unit.  Proton’s mass.  

So, (1a)x(2a) x [(22/7) / 3 ]  or,  

 [(Electron mass) / ( 0.413334 x 10 )^2  ] x (Pi)^9 x  [(Pi) / 3 ]  = PROTON’s MASS.  

We know that, as per (e=mc^2) equation.  Proton’s mass = 1.672623e-27 Kg.  

 

Overall, these points underscore the intricate relationships and constants that define the behavior and characteristics of fundamental particles and the energies associated with them. They present a framework for further exploration and understanding of the principles governing atomic and subatomic phenomena.

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