“ASOLSD – proof number 16”

                  sree Debasish Dasgupta. India

Honarable scientist Bhore, as per his opinion it is seen that every orbit of an Atom moves around in a particular rule.(pic-7).My opinion is that every electron’s redius is same with proton’s redius.So ,porton’s radius = electron’s redius’s Induction area.

As per this view,if we think (Imagination) proton’s redius = 2 unit,then,we can draw a circle of 2 unit redius.Now ,if we draw same redius circle on it ,we can see ,1st circle or,protn is the centre of 6(six) circles.2nd time,it is 12 circles,3rd time is 18; circles.,like this ,every time 6 circles increase each time.

Now,if we divide 6 circles divided by 3,then,(6/2)=2, same, 12 circle (12/3)=4,like this,

As per Bhor’s rule,as n² orbit, 2n² =electron No.-

1st orbit =2, 2nd orbit =24circles,(24/3)=8,3rd orbit =54 circles(54/3=18 electrons can reside,[shown in black coloured electron in the picture--7],Like this, equal number of electrons increase in different orbits.

(Next,if we imagine proton as top point and we draw Equilqteral triangle then,   in the picture 7A)

example – 1st triagle aPb’s side ap =1 circle,2nd tringle cPd’s side =4 circle, 3rd ...9 circles,so root 1-1,root 4=2,root 9=3( 2 radius = one diameter or one circle ),these are all number of orbit.(in picture7B ASOLSD  ).

.If we calculate the perimeter of the tringle,we can see every triangle ‘s perimeter root 3 =1.73205 unit wise it will increase.

example — [perimeter of tringle 3a, hare number of DIAMETER x3 (2 redius = 1 Diameter )] 1st—1x3=3 ,root 3 = 1.73205,,2nd 4,-- 4x3=12;  root 12 = 3.464101. 3rd—9,,9x3=27,,,root 27=5.196152,

4th-16,,16x3=48,,,root 48=6.926152. 

Now two perimeter added,(1+9,2+8, 3+7,,4+6) = 17.3205 which is 10 times of root 3 ,so it can not be more than 17.3205. 5 number orbit’s perimeter if added to any other peimeter it can not be 17.3205 unit,never. so 5 number orbit’s perimeter is half of 17.3205 unit,then ,5 number orbit is the joint place of two groups.so no electron can reside or,stay here.

Here,if we multiply perimeter of the circle by 2 and root so,root-2x2 Pi’ ‘r’ or root 4 ‘Pi’ ‘r’ like this it is seen every orbit 3.544 unit wise increase and 5 number orbit 17.72unit which is almost 2 time of tringle’s perimeter (8.66025 x 2 =17.3205),and every electrn is not globe but circuler.

In my view,eighten (18) circle will be in 2nd orbit,so 6 lectron’s,like this,if we calulate geometrical figure then ,different information as well as condition will come out,which give new direction to the up coming science and technology.

***[ I am sree Debasish Dasgupta extremely sorry that I have done a small misteke in “ASOLSD” –15 no proof that I have written by misteke (printing misteke) that Equal “Mass” that will be Equal “Energy” in every orbit.]

So,I take it as my own social responsibility to attract all the views of honourable scientist of the world.I have no knowledge that how much importance I will get ,but i have tried my responsibility with best of my abilities.Rest,all depends on your opinions about my research (thought).

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