Husk of Potato

                          .sree Debasish Dasgupta.                      

Abstract

After lot of permutation – combination deduced some rule [ Electron Volt = Frequency x 0.413334, Energy = Mass - (mass /10), Energy = Force / Displacement etc.]   from the article, ‘Atomic Mass – Energy-Primary Colors’ and it’s related. That every matter creates or destroys in two parts. Both of them are quite opposite to each other in principle.

As per this, every organic cell or, plant life (Botany) every matter has its waste products which obstructs the growth of creation of the ‘living cell’. It can be seen by following the cell that if we want to control any Virus or, germ can be destroyed by using their own waste on them in a proper method. They can be destroyed totally in this method. By this, lot of fatal diseases like AIDS, Cancer, Jaundice, etc. can be controlled by deducing their Anti-dote or, method of over come through it.

Experiment:

It feel through this experiment that in human body to control the Diabetic limit by ‘potato husk’.

First, have to take out the peel out of the potato, then, it have to take that particular husk to be washed properly and to be eaten at a particular limit so, that some type blood starch to be controlled. [ It will be must better when 1^st time attract in human body; blood sugar limit between 140 – 200. and also cause due to hypertension; sleeplessness, etc ] 

Dose: 25 – 40 gram weight potato husk to be boiled or, to be fried in light oil or, paste of potato husk and it can be eaten in morning time at breakfast or, in lunch at noon time food. If it is needed, can eat it two times a day… as per blood sugar test result. 

After 3 to 7 days Diabetic problem are in control, then it should minimise the quantity slowly.

    Conclusion

 Some type blood starch to be controlled.

It is possible, because this potato husk is just the opposite starch of that starch creating element. If it is used in body, it will work as opposite starch of the Diabetic element present in body.

“Atomic Gravity” Sree Debasish Dasgupta (Image)

“Atomic Gravity” Sree Debasish Dasgupta

                              “Atomic Gravity”

                                  Sree Debasish Dasgupta

We are indebted to those scientist .[ The great “Einstein”, sir “Newton”, “Bhore” and lot of others Scientist ] who given new direction to our knowledge by doing hard work relentlessly day by day .I am making out some investigations after checking out some contributions by themIt is not my any kind of self – importance and also have not any mentality to – disrespect  to any scientist.

AS I am not beigin a PROFETIONAL SCIENTIST –From that point of view it seems

After the broadcast (In SOCIAL media) of my discovery lot of derogatory and defame comments are heard- [This paper was  rejected on without peer review, on the grounds that it is not scientifically sound…Like this] --- which was cause that no organization give me recognition. It is to dishearten. MY GRIEF.

I take it as my own social responsibility to attract all the views of honorable scientist of the world. I have tried my responsibility with best of my abilities. It’s my ardent wish that my scientific formulas are being used for the benefit of human society  Rest, all depends on your opinions about my research (thought).

## Honorable scientist Bhore, as per his opinion it is seen that every orbit of an Atom moves around in a particular rule.(pic-7).My opinion is that every electron’s radius is same with proton’s radius’s ,proton’s radius = electron’s radius’s Induction area.

As per this view,

In my article  F = Es or E = F/s or s = F/E. (picture no ASOLSD 9 & 9A)  we have discussed on different calculation of  “Neutron” ‘Proton’ ‘Electron’s Force, Energy,etc in Atom's orbit .

NOW – As per great scientist Honorable NEWTON’s law of Gravitation,

G₁= F x r ^² / m^{^2}

G₂= F x r ^² / m₁m₂  

[ as per my (sree Debasish Dasgupta) calculation : Force = 5.3…unit, Radius = Atomic distance here 0.53 unit, mass = atomic mass, like Neutron, Proton, Electron etc.] 

 We know one Neutron mass = 1.6749 x 10^{^-27} Kg. and one Neutron 1839 times heavier than Electron.

So as per my view One Electron mass   1.6749 / 1839 = 0.0009 unit. One Electron mass 

Hare ‘F’= 5.3…unit, mass= 1.6749, ‘r’= 0.53unit, (as per scientist Bhore ‘H’ atom’s 1^st orbit radius.) Electron mass= 0.000904 unit (as per my calculation electron mass 9.04unit or 0.000904 unit, For details Please see “A STORY OF LATEST SCIENTIFIC DISCOVERY)

Gravitation of  Neutron ---

G = F x r ^² / m^{^2}  

‘G’₁ =(F) 5.3… x (r) 0.53^²… / (1.6749)^{^2} = 0.53..unit That means ‘G’ for an Atom is 0.53…unit,

Again as per G= F x r ^² / m₁m₂ ‘G’ or Attraction or Repulsion between Neutron and Electron.

‘G’₂ =(F) 5.33 x r (0.533)^² / (N)1.6749 x (e) 0.000904 = 1.5141 / 0.0015141= 1000unit .

As per law “g” = GM / R^{^2}

“g” (neutron) =(0.533 x 1.6749) / 0.533^{^2} =(0.8927217 / 0.284089) = 3.1424 or one Pi

“g” (electron) =(0.533 x 0.000904) / 0.533^{^2} = 0.000481832 / 0.284089 = 0.001696 unit.

Now “g” (neutron) x “g” (electron) = 3.1424 x 0.001696 = 0.00533 unit.

{“g”(n) x “g”(e)} x “G” = (3.1424…x 0.001696) x 1000 = 0.00533 x 1000 = 5.33 unit Force. 

[ as per “G”₂ – 1000 root = 31.6227766,root 31.6227766 = 5.6234, 5.624 x 2 = 11.25 (nearer) as per my calculation it is minimum Angel of electron see my all article.

Again as per Coulomb rule electric field and intensity of on electric field ---

(a) ‘E’ = Q / k.‘r’^{^2} = “E” = 1.602 / 0.5334 = 5.63 x 2 = 11.25 (nearer) .

Root 5.624 = 2.371 already explain about 2.371 and it’s next calculation in “COSMOGONY” part 1&2,

(b) Force = Q₁ X Q₂ / k.’r’² (k= permittivity or dielectric constant) as per Coulomb rule.

F = (1.602 x 1.602) / (0.5334)^² = 9.02 unit

“E’ = 5.63 as per (a) and ‘Torque’ = p x E or “T” = 5.63 x 1.602 = 9.02.

(Torque on an electric dipole in a uniform electric field)

Please see about “9” in my article.

Conclusion :

[ Transformation of Energy & Law of Conservation of Energy ]

.1) ‘G’1 = Gravitation of  Neutron = 0.53… unit

.2) ‘G’2 = Gravitation between Neutron and Electron = 1000 unit

.3) “g”1 (neutron) = 3.1424 or one Pi

.4) “g”2 (electron) = 0.001696 unit.

.5) “g”1x ‘g’2 x G2 = 5.33 = Force. [see “Atomic Gravity” Image]

*** This total calculation should be multiplied (or divided) by 10 or, multiplier of 10 like 100,1000,10,000 to convert it from current unit to different unit like- Kg, gram, cm,sec, etc. I have done all calculation without any power.

For details please read my all articles at SOCIAL MEDIA, “A STORY OF LATEST SCIENTIFIC DISCOVERY” at FACEBOOK, TWITTER, BLOG by GOOGLE SEARCEH. Sree Debasish, sree Debasish Google, scientist sree Debasish, sree Debasish Dasgupta,sree Debasish Nasa, mygov.in sree Debasish etc related and images,

 [nb.> “A STORY OF LATEST SCIENTIFIC DICOVERY’’—‘ASOLSD’ and related artiale by sree Debasish Dasgupta # No part of this publication may be reproduced or any form or any means or any information,  without permission from the Author or chief in charge by:MNGRWS]

এই CERTIFICATE আপনাদের অবদান, তাই সকলকে উৎসর্গ করতে পেরে ধন্য হলাম, यहि CERTIFICATE आपकी दान है , आप सबको निबेद्न करताहु

  

এই CERTIFICATE আপনাদের অবদান, তাই সকলকে উৎসর্গ করতে পেরে ধন্য হলাম,

यहि CERTIFICATE   आपकी दान है , आप सबको निबेद्न करताहु  

F = Es or E = F/s or s = F/E.

                       F = Es or E = F/s or s = F/E.

                                              Sree DEBASISH DASGUPTA

                                          * SUPPORTING  CLUE for  E = F/s *

We know one proton is 1837 time heavier than electron, and one neutron mass value equal energy = 938 MeV.

So  939/1837= 0.511 unit energy equal of one mass of electron.(And  angel 11.25 / 22 = 0.51113 ).

 When collusion with one “L” that moment – 0.511 x 0.413334 = 0.2112796 add one time and space 0.2112796 + 1.296 = 1.5072796 unit energy. As per my opinion E = m – (m/10).

Mass = ( ex10) / 9 = (1.50728 x10) / 9 = 15.0728 / 9 = 1.674755 unit mass.

And again 1.5072796 x 9 = 13.56 unit energy ( as per Scientist ‘Bhore’ I have several time write about that in my article in short “ASOLSD” see also picture 6)

1837 X 5.334 (Force) = 9798.588.Root = (i)  98.98766 Root = (ii) 9.94925 Root = (iii) 3.15424 Root = (iv) 1.776 Root = (v) 1.332

..(i) nearer 100 (ii) nearer 10,(iii) nearer ‘Pi’. Or ‘h’ bar (iv) mass (v) 4/3,  (as per my opinion see about digit “10” )

1837 x 1.602 (energy) = 2942.874 Thirty two(32, max electron in one orbit) Root = 1.283509 x 7 = 8.98456 (C² as per my calculation)

1837 x 1.296 (Time & Space) = 2380.75 Twenty seven (3x3x3=27) Root = 1.3337=(4/3) for details read my all article at Facebook, Twitter, Blog’s By google search.A Story Of Latest Scientific Discovery.

Now ---1837 x 1.11* (see latter) = 1935 Sixteen Root = 1.6047 (energy), Square = 2.5754 Square = 6.63273 (Planck Constant) Square = 43.98 =14 x Pi ,(See About 42/3=14 , in my article)

*** That means 1839 times ,Force, energy, time etc. present in a neutron.***

[ So Total Force x energy x time & space =  9798.588 x 2942.874 x 2380.75 = 68651330478.747,  68651330478.747  nine Root (9) = 16, [ SEE Picture No 9,& 9A]

And when add total time 1935 , 68651330478.747  x 1935= 1328 4032 4476375.445, if we Root it step by step after 7^th step we will get see 1.289254, 1.289254 x 7 = “9”, ( or Root 128, For Why 128 ?, 0.53 x 100 = 53, & 53 / *0.413334* = 128. & 3 x 3 =”9” , 3 x 3 x  3 = 27) and if  1328 4032 4476375.445 twenty seven (27, 3x3x3 = 27) Root  = 3.33, (Displacement)  Next … several time I write about 1.289254 in my article ASOLSD.

 So that means : (1328 4032 4476375.445  / 1.289254 ) = 103036581213923.28043969613435366  times 1.289254 is present in a neutron .

Let us see : - step by step Root to  103036581213923.28043969613435366 ,after sixth (6^th) step (or 64 Root over)  we will get result 1.65559 ,we know one neutron 1839 times heavier than one electron, 1839 x 9 = 16551 divided by 10,000 = 1.6551 it same uint.And after 7^th step (or 128 Root over) get resut 1.2866976140160393105164440327068 x 7 = “9”  

Again if Nine Root 103036581213923.28 get result 36, (36 x 10 = 360 degree angle 36 x 100 = 3600 sec. Time.) AND (27) twenty seven ROOT GET 3.3, For clear understand see picture 9 & 9A  ]

*1.11 to the power 32** = 28.2056 Root (as per a² +b²=c²= 28.17 & 5.31 is10 times of ‘H’ atoms 1^st orbit radius, 0.53, or as per my opinion force OR Force for revolving electron around the orbit)

As per formula c = Root over (a² + b² + 2ab) = Root over (a + b)² = a + b

..a + b = (4.13334 + 3.33) = 7.46334, Root 7.46334 = 2.73191 Root = 1.653 Root = 1.285632.

1.285632 x 7 = 8.999 or “9”. (4L= 0.413334x4=1.653336)

Please see details of ‘7.46334’at  “A Story Of Latest Scientific Discovery”, IOSRPHR Journal Vol-8,Issue-5,Version-1 Page No.28, OR Social Media by *GOOGLE* search.

As per my view *1.11 is Time need for create Displacement to Acceleration. In the time of revolving electron around the orbit. So Time = Root 1.11=1.05365 unit.

We know Force = mass x f  (Acceleration) = mass x (changing motion / Time) = Momentum/Time, ie changing of Momentum = Force x Time.

So factor of time & mass, as per my view E= F/s or s = F/E. or F = Es [Force=5.334, Energy = 1.602, Displacement (s) = 3.33, Time = 1.05365,Time square= 1.11 ]

Here Acceleration = (3.33 /1.11) = 3 unit.

So as per law F = ma, m=F/a or mass=5.334/3= 1.778 unit. [When Time is 1.11]

We know As per law P=mf or P = mass x (v – u) / time,[Here v= end & u= starting motion, ]

P = 1.782662 mass x (3.33 – 3 = 0.33) / 1.11 = 0.58828 / 1.11 or 0.53 it is radius of “H” atom’s 1^st orbit. And this total calculation makes from 0.53…unit.

NOW – see also –

(a) 1/3 = 0.33…,

(b) 5.334 / 1.05356 = 5.06283458 , 5.06283458 four Root = 1.5 it is ½ of 3, (some time we use ½ spin ext.)

© 3.33 / 1.296 (Time & Space) = 2.569,Root 2.569 = 1.6029 unit, all most one energy.

(d) 3.33 / 0.413334 = 8.056321, 8.056321 eight Root = 1.297 all most 1.296 (Time & Place)

(e) 5.3 + 1.2919 (constant of Visible Light) = 6.5919, 6.5919 sixteen Root = 1.125 x 10 =11.25 angle. [ already explain about 11.25 & 1.125 in my article ]

(f) 5.334  + 1.2919 = 6.625 Planck constant. Root = 1.6044 unit energy, [Please see COSMOSGONY 1&2, and “E = m – (m/10)” articles ]

##   (g) 32** Root = 5.6568, Root = 2.378, Root 1.54221,Root 1.1241,Root = 1.11, Root= 1.055 It is time for produce an atom from Neutron. Four Root 1.24eV= 1.055.,Force= 5.334, Root sixteen 5.334 = 1.11.

    [except 32 All are already explain in COSMOGONY & others article SEE also E = F/S, ‘Pic 9’ ]

[ Establish My all opinion & all formula and also L= 0.413334,all most TRUE]

 For details please see my all articles, “A STORY OF LATEST SCIENTIFIC DISCOVERY” at FACEBOOK, TWITTER, BLOG by GOOGLE SEARCEH.

[ No Part of ALL this publication may be reproduce or any form or any means or any information without permission from the author or chip in charge :by:- M.N.G.R.W.S ]     

 

                            বিজ্ঞানের ভাষা 

                  Sree DEBASISH DASGUPTA

আমি দেখেছি বা দেখছি যখনি কোন ছাত্র বা ব্যক্তি বিজ্ঞান বিষয়ে কিছু আলোচনা করে তখন বেশি ভাগ সময় তারা অসহায় ভাবে বলে বিজ্ঞান বুঝিনা ,বা আমি বিজ্ঞান বিষয় নিয়ে পড়াশোনা করিনি।

তাদের নিজেদের মধ্যে ভাবনাটাই এমন স্থানে দাঁড়িয়েছে যে বিজ্ঞান হচ্ছে বিশেষ বিশেষ মানুষের জন্য।

তার জগৎ ও আলাদা, এটা দূর করতেই - বিজ্ঞান বিষয়টি অনুধাবন করতে যাতে সহজ হয় সেই দিকে নজর দিয়ে আমি প্রতিটি প্রবন্ধ রচনা করার চেষ্টা করেছি।।

 আজ বিজ্ঞান একটি ভয়ঙ্কর স্থানে প্রতিষ্ঠিত হবার কারণ নানা রকম বাধা নিষেধের ঘেরাটোপে রেখে সাধারণের কাছে পরিবেষণই দায়ি।।

আমি নিজে এর ভুক্তভুগি –

সামান্য একটি প্রবন্ধ (যদি তা অতি নিন্মমানের ও হয়) কোন  প্রতিষ্ঠিত জার্নালে প্রকাশ করতে হলে তাদের দেওয়া নির্দেশ অনুযায়ী – ভাগ ভাগ করে প্রতি ভাগের আবার আলাদা আলাদা পরিমাণের,ডিজাইনের, অক্ষর ইত্যাদি নানা ফরমান মানতে হবে তবেই তারা লেখাটি পড়বেন,তারপর অনেক ধাপ পেরুলে তবে হয়তো প্রকাশের বিবেচনা করা হতেপারে।

যদি লেখাতেই এত নির্দেশ মানতে হয় এবং তা প্রকাশ করতে প্রতি জার্নালের জন্য  বিভিন্ন পদ্ধতি প্রশিক্ষণ গ্রহণ করতে হয়, তবে সহজেই অনুমান করা যাবে বিজ্ঞান চর্চার মধ্যে কত বাধা,কেমন ভাবে একে সাধারনের বোধের অনুপযুক্ত করা হয়েছে।।

আমি একটি প্রতিষ্ঠিত জার্নালের আমার লেখা “A STORY OF LATEST SCIENTIFIC DISCOVERY” প্রত্যাক্ষানের ভাষা নিবেদন করছি।। তারা পড়েই দেখেননি! হতে পারে অতি নিন্মমানের।।

Dear Debasish,

Thank you for your email and apologies for the delayed reply. This paper was  rejected on 17^th May without peer review, on the grounds that it is not scientifically sound. Therefore, we do not require any further correspondence regarding this paper. Furthermore, as per our appeal policy, it will not be entitled to an appeal, as the paper was not sent for peer review.

We thank you for submitting your paper to Royal Society Open Science.

Best wishes,

Thadcha

জানিনা এটা অতি শিক্ষার অহংকারের বহিঃপ্রকাশ কিনা।

আবার অন্য একটি বৃহৎ সংস্থার লেখার উদারহণ দিচ্ছি  যা আমাকে উৎসাহ দান করেছিল ,NASA – একটি বিশেষ গুনের অধিকারী, তারা যে কোন অবহেলিত বিষয়ের দিকে নজর রাখেন, যদি সেই অবহেলিত বিষয় থেকে মুল্যবান কিছু বেরিয়ে আসে সেই উদ্দেশ্যে। আর তার মুল্যও দিতে জানেন।এই মহৎ গুণই তাদের প্রতিনিয়ত উত্থানের অন্যতম কারণ।।

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ASOLSD PICTURE No 9.    E = F/s