Energy X Mass = m2

                                    Energy X Mass = m²

                             Sree Debasish Dasgupta

In past, I have discussed different rule and method of molecules in all Article of Light and structure of light. All thought, No famous journal have published my Articles, but, LOT of scientists have appreciated my Articles and more importantly, lot of science researcher accepted their inability of courageousness  to publish my article on their journal/magazines.

I can SAY it with confidence that all the social media for example ‘Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc. have given LOT of support to my attempt and as a result,

Mendeley.com, (by Elseveier.Com), have published my project article on Data cite of them.

I can not find any expression to congratulate them ( compulsorily : Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc,) for their gratitude to my work. 

      

   Introduction :    In, the present article for support and favour  of past articles E=F/s, and unavoidably others articles.

“A Story Of Latest Scientific Discovery”  “Atomic Mass Energy Primary Colours”   “Atomic Time Space” and Also Latest Article

         “ Atom to Nucleus” 

I have discussed new logic and formulae which have to be understood through FB, Blog, Twitter, Mendeley.com, ORCID, etc. GOOGLE search and also I request to study each article discussed in the past.

                         Without, unit power I have shown only numbers [Like : approx mass of one particle (Neutron) 1.679616 x 10^-27 Kg in that place 1.679616 unit]  the whole calculation to express present unit by using 10, or multiple of 10,

As per my calculation :

One Mass ( Before Nucleus) Divided by One mass (After Nucleus) = 1.054, Unit , Here (M / m) = 1.054 unit  ( All Approximate unit).

One Mass ( Before Nucleus) Minus  One mass (After Nucleus) = 0.1 Unit.

Here (M-m) = 0.1 unit.

One Energy (After Nucleus) Divided By One energy  (Before Nucleus) = 1.062 unit , Here (E / e)= 1.062 unit.

 One Energy (After Nucleus)  Minus  One energy  (Before Nucleus) = 0.09 unit , Here (E - e)= 0.09 unit. (Please see ‘Atom to Nucleus’ for Details)

(All unit Constant for Nuclear action and reaction,  All unit Approximate).

#                        E² = E x M x (E – e) / (M – m)  

For  example: [(1.602 x 1.78) x 0.09 ] / 0.1 = 2.566404 unit. = E^{2 ,}

  Root Over 2.566404 = 1.602 unit.= E,

#                          M² = [ (E x M) / (E – e)] x (M – m)

Examp:  [ (1.602 x 1.78) / 0.09 ] x 0.1 = 3.1684 ( it is acceleration of ‘f’ either energy). Root Over 3.1684 = 1.78 unit, = M.

#                             E = [ M / (M – m) ] x (E – e)

Examp :  [ (1.78 / 0.1) x 0.09 = 1.602 unit. = E.

#                             M = [ E x (M – m) ] / (E – e)

Examp : [ (1.602 x 0.1) / 0.09 = 1.78 unit = M,

#                              E x M = m²

Examp : 1.602 x 1.78 = 1.6886²  unit  = m² 

Hence : m²  = m x m, one ‘m’ for mass and others ‘m’ is equivalent  energy which is internal (sleeping) Energy of Mass. This Energy create Mass to mass.

Example   ( 1.602 x root over (10/9) = 1.6886 unit

                        Or,   m = E x (M / m) = 1.602 x 1.054 = 1.6885...unit .

                        Same for   m x (E/e) = M,

This process is continue, so we can create many  different type of formula, for mystery or World.

Conclusion :-

1.   One Mass ( Before Nucleus) Divided by One mass (After Nucleus) = 1.054, Unit ,

One Mass ( Before Nucleus) Minus  One mass (After Nucleus) = 0.1 Unit.

One Energy (After Nucleus) Divided By One energy  (Before Nucleus) = 1.062 unit ,

 One Energy (After Nucleus)  Minus  One energy  (Before Nucleus) = 0.09 unit ,

2.   E² = E x M x (E – e) / (M – m), 

3.   M² = [ (E x M) / (E – e)] x (M – m)

4.   E = [ M / (M – m) ] x (E – e)  

5.   E x M = m²  Or, m = E x (M / m) & m x (E/e) = M,