Sunday, 28 April 2019
Energy X Mass = m2
Energy
X Mass = m2
Sree
Debasish Dasgupta
In past, I have discussed different rule and method of
molecules in all Article of Light and structure of light. All thought, No
famous journal have published my Articles, but, LOT of scientists have
appreciated my Articles and more importantly, lot of science researcher
accepted their inability of courageousness
to publish my article on their journal/magazines.
I can SAY it with confidence that all the social media
for example ‘Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc. have given LOT of
support to my attempt and as a result,
Mendeley.com, (by Elseveier.Com), have published my
project article on Data cite of them.
I can not find any expression to congratulate
them ( compulsorily : Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc,) for their
gratitude to my work.
Introduction
: In, the present article for support
and favour of past articles E=F/s, and
unavoidably others articles.
“A Story Of Latest Scientific Discovery” “Atomic Mass Energy Primary Colours” “Atomic Time Space” and Also Latest Article
“ Atom to Nucleus”
I have discussed new logic and formulae which have to be
understood through FB, Blog, Twitter, Mendeley.com, ORCID, etc. GOOGLE search
and also I request to study each article discussed in the past.
Without, unit power I have shown only numbers [Like : approx mass of one
particle (Neutron) 1.679616 x 10-27 Kg in that place 1.679616
unit] the whole calculation to express
present unit by using 10, or multiple of 10,
As per my calculation :
One Mass ( Before Nucleus) Divided by One mass
(After Nucleus) = 1.054, Unit , Here (M / m) = 1.054 unit ( All Approximate unit).
One Mass ( Before Nucleus) Minus One mass (After Nucleus) = 0.1 Unit.
Here (M-m) = 0.1 unit.
One Energy (After Nucleus) Divided By One energy (Before Nucleus) = 1.062 unit , Here (E /
e)= 1.062 unit.
One Energy
(After Nucleus) Minus One energy (Before Nucleus) = 0.09 unit , Here (E -
e)= 0.09 unit. (Please see ‘Atom to Nucleus’ for Details)
(All unit Constant for Nuclear action and reaction, All unit Approximate).
# E2
= E x M x (E – e) / (M – m)
For example:
[(1.602 x 1.78) x 0.09 ] / 0.1 = 2.566404 unit. = E2 ,
Root Over
2.566404 = 1.602 unit.= E,
# M2
= [ (E x M) / (E – e)] x (M – m)
Examp: [ (1.602 x
1.78) / 0.09 ] x 0.1 = 3.1684 ( it is acceleration of ‘f’ either energy). Root
Over 3.1684 = 1.78 unit, = M.
# E = [
M / (M – m) ] x (E – e)
Examp : [ (1.78 /
0.1) x 0.09 = 1.602 unit. = E.
# M =
[ E x (M – m) ] / (E – e)
Examp : [ (1.602 x 0.1) / 0.09 = 1.78 unit = M,
# E x
M = m2
Examp : 1.602 x 1.78 = 1.68862 unit =
m2
Hence : m2 = m x m, one ‘m’ for mass and others ‘m’ is
equivalent energy which is internal
(sleeping) Energy of Mass. This Energy create Mass to mass.
Example ( 1.602 x
root over (10/9) = 1.6886 unit
Or, m = E
x (M / m) = 1.602 x 1.054 = 1.6885...unit .
Same for m x (E/e) = M,
This process is continue, so we can create many different type of formula, for mystery or
World.
Conclusion :-
1. One Mass ( Before Nucleus) Divided by One mass (After
Nucleus) = 1.054, Unit ,
One Mass ( Before Nucleus) Minus One mass (After Nucleus) = 0.1 Unit.
One Energy (After Nucleus) Divided By
One energy (Before Nucleus) =
1.062 unit ,
One Energy
(After Nucleus) Minus One energy (Before Nucleus) = 0.09 unit ,
2. E2 = E x M x (E – e) / (M – m),
3. M2 = [ (E x M) / (E – e)] x (M – m)
4. E = [ M / (M – m) ] x (E – e)
5. E x M = m2 Or, m = E x (M / m)
& m x (E/e) = M,
Friday, 26 April 2019
ATOM to NUCLEUS
Sree DEBASISH DASGUPTA
In past, I have discussed different rule and method of
molecules in all Article of Light and structure of light. All thought, No
famous journal have published my Articles, but, LOT of scientists have
appreciated my Articles and more importantly, lot of science researcher
accepted their inability of courageousness to publish my article on their
journal/magazines.
I can SAY it with confidence that all the social media
for example ‘Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc. have given LOT of
support to my attempt and as a result,
Mendeley.com, (by Elseveier.Com), have published my
project article on Data cite of them.
I can not find any expression to congratulate
them ( compulsorily : Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc,) for their
gratitude to my work.
Introduction : In, the present article for support and
favour of past articles E=F/s, and
unavoidably others articles.
I have discussed new logic and formulae which have to be
understood through FB, Blog, Twitter, Mendeley.com, ORCID, etc. GOOGLE search
and also I request to study each article discussed in the past.
Without, unit power I have shown only numbers [Like : approx mass of one
particle (Neutron) 1.679616 x 10-27 Kg in that place 1.679616 unit] the whole calculation to express present unit
by using 10, or multiple of 10,
F= root over 9M/r
We know F=mv2/r. mv2/r= G.M.m/r2,
or, v2=G.M/r, or, v= root over G.M/r, or v2r=G.M, or, G=v2r/M
[F=force, G=Gravity, M=mass v=velocity, r=radius, as per my past calculation F=5.3…, G=0.53…,
M=1.679616, velocity=1.296, (and Time = 3600 sec./1000=3.6, space 360 degree/
1000= 0.36, 3.6x0.36= 1.296 all ready explain about time and space)]
* F = mv2/r,
= (1.679616 x 1.2962) / 0.53 = 5.3…, unit.
* mv2/r = G.M.m/r2,
or, v2=G.M/r, = 0.53 x 1.679616 / 0.53 = 1.679616 unit.
Or, v= root over G.M/r = 1.296 = root
1.679616, (Orbital velocity of atom)
Or, v2r =G.M = (v)1.2962
x (r) 0.53 = G.M. = 1.679616 x 0.53 = (G) 0.53 x (M)1.679616
Or, G= v2 r/M, G= 1.2962
x 0.53 / 1.679616, = G = 0.53.
.* w = v/r = root over G.M / r3,
(orbital angular velocity of atom ‘w’)
Or, w = 1.296/0.53 = 2.44528. or w = root over G.M / r3 = root 0.53 x
1.679616 / 0.533
Or G.M
= root over [ (0.53 x 1.67616) / (0.53 x 0.53 x 0.53)] = 2.44528 = w .
Now as per this calculation :
F= mv2 / r, root over mc2
/ r, or F = root over 9m / r. (as per my calculation c2 = 9)
[see also : as per E = m – (m/10) rule.
E=1.679616 – 0.1679616, = 1.511644. unit.
And 1.6021736179 x (10/9) = 16.021736179 / 9
= 1.7801929087.
1.78019290872 = 3.16908679246,
3.16908679246 x 0.53 = 1.679616 (same value M)
3.16908679246 / 0.53 = 5.979409, root
5.979409 = 2.44528 (same value ‘w’)
(3.169086792462 = 10,
3.16908679246 it is nearer of plank h ber,)
Next Calculation see image of ‘ATOM to
NUCLEUS’
Conclusion : -
1. 4/3
Pi = (Binding Energy of Proton or Neutron) / (mass X Acceleration)
2. 0.1
unit and 0.09 unit is constant unit.
3. Force
= Root over (9 mass / r either 9mass / G.
4. m /
r = f (acceleration) either (m/G= f ) etc.
Reference : -
‘A Story Of Latest Scientific Discovery’ 1st
part, ‘Atomic Mass Energy Primary Colours’
‘Atomic Gravity’ ‘Atomic Time Space’ and Google.com,
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