“A  STORY  OF  LATEST  SCIENTIFIC  DISCOVERY’’

                     “ Sree Debasish Dasgupta”

Today , the whole world is dependent  on science. We are indebted to those scientist who given new direction to our knowledge by doing hard work relentlessly day by day .I am making out some investigations after checking out some contributions by them.These investigations are very small and nothing. Here we get all calculation’s also considered original or base or origin number has taken ,for examp- mass of electron 9 x 10^-29 gm…one charge is 1.602 x 10^-19 culamb, -13 electro volt in that place 9 unit,1.602 unit, 13 unit ext.ext. has been kept as a unit. Today,we make different units in multiple of 10 or divisible to 10 for easy understanding. But it should be said that I am also to take the previous count only for returning to principal unit,or to make it equal with present unit.

[ LET US SEE THE MATTER UNDER MAGNIFYING GLASS          IN MAGNIFIED POSITION for easy understanding ]

THE TROPIC OF INVESTIGATION :TO PROVED :-

(A)Visible light and atoms different  quantum digit ,wave length, frequency, charge, energy, orbit,   

(B) Original or main color is four “Red”& “Yellow” (T1 group), “Green”& “Blue” (T2 group) .

 (C) The proof of my discovered rules – (energy or eV =frequency x 0.413334,)& (Mass x charge = eV) etc.

By this we can make out the wave length ,frequency, or shall make out the count directly.

(D) The mother number or mass, which is shown as “L”,

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(L=0.413334)  The whole calculation is done by keeping the energy of photon =1.24 eV,     whole wave length field is known as a triangle, area ½ x base x height,  The area of  triangle =3 X 0.413334 = 1.24 sqare unit and -1.602 x 1.24=1.2919  is constant.The main and primitive triangle is seen as an area of the triangle or ,to calculate the light wave length by multiplying it with 1000000. As ,1.24 x 1000000=1240000.divided by 4 ,each area is calculated,so 1240000/4 =31000 which is shown in picture no.5.

It is seen two Red‘s are inside  T1 group, Again if we add up the frequency or quantum no.  of “Red” & “Yellow”  and divide by 2 we will get frequency of “Orenge”.  Same T2 group “green” + “Blue” divide by 2 we will get frequency of “Cyan”color.

Apart from this ,to help  geometrical shape drawing we can get same area as by dividing it with 2 to wave length of Red and multiply it with quantum of “Red”,  same by dividing it with 2 to wave length of Yellow and multiply it with quantum of Yellow. (This same area consisting triangle met when Orange is created, )  as we add up  (both area R&Y) and dividing it with quantum of Orange we can get wave length of  Orange.

Same process for (T2 group) Cyan color .So original color is four it is proved.

T1 group’s Red,Orange ,Yellow’s addition of frequency is less than of T2 group, which is equal to  Red frequency quality,so,one more “Red” is in T1 group.So T1,group’s total number is four,(Red ,Red ,Orange, Yellow).

From 1^st law,it is seen that each T1,T2, & T3,group’s energy is if added then,T1 + T2 = T3, now,T1,& T2 group’s every addition of mass inside the wave length is =, Hare ,[pic 6]           

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0.413334 which is small to smallest 0.413334 x 4=1.6534   unitary mass which is near to the hydrogen atomic molecular Atomic mass.

Electron which is revolving in an orbit unitary mass is 9 unit [which can see and use in different calculation later]

In pic.5A no [except T3 group ] we will get a list of T1,T2’s energy ,mass.It is proved that if we divide charg to total mass which is equal to total energy.

## If we look at the principle of scientists Bhor & Balmer (pic 6) one ‘H’ atom or atom’s energy is given according to each orbit. In this picture ,the middle part of the two orbits is shown by the energy house [which is seen on 7,1,2,3,..number]

Again Bhor’s orbit is known as A,B,C, ext.so here,first orbit middle part and 7 no house/cell’s centre.[Bhor 1^st orbit =A]

Now same process of visible light we can get 1^st & 3^rd quantum or frequency addition is divided by 2 and we will get frequency or quantum no of 2^nd cell’s. same way T2 group’s 4^th & 6^th cell’s quantum or frequency addition is divided by 2 and we will get frequency or quantum no of 5^th cell’s.

In T3 group 7^th cell’s quantum no = 1^st & 6^th cell’s  quantum  addition is divided by 2 and we will get quantum. And other way for T3 we can see pic. 6A.                                                                                 Page No –3

It is proved that every energy status is changed by following one rule. And three group’s are totally separate.  

## Four group’s in an atom mass, energy and charge always change among each other and transform to another energy from one as energy universality rule. Every energy is encompassed in a sickle after each and every action or, reaction.  Which is shown in pic. 6A.

If we pick this 0.1335 unit as frequency,then according to 1^st rule,it’s energy =0,1335 x 0.413334=0.055 unit is multiplied by 10 then,it is equal to electron weight by a special unit (.055amu). Then ,if we calculate this as frequency then , it is equal to unitary unit.

Again ,if we multiply it with 0.1335 x 4 = 1.2919 then all 01.2919unit’s are equal to constant.

So- one neutron is the source of one “H”atom  then 2 “electron” means mass or energy is the replacement of one electron mass =9unit (one still mass of “e” =9.1 unit)

# One newtron is heavier than 1839 time’s.9 x 1837 = 16551 unit.

## One proton is heavier than one electron 1837 times. 9 x 1837=16533.unit.

1 newtron’s mass is eqal to 939.7 energy

1 proton’s mass is eqal to  938.7 energy

So, it is easily presumed that 2^nd energy or,2^nd mass is the main component of electron and proton of the concerned ENERGY of electron .  Which is stored in the “CHAIN’’ of the concerned electron.                      [Page No—4]

             

  IF WE SEE,THE MASS OF “e” FROM ANOTHER VIEW

 Mass of ‘e’ 9.1 unit equivalent to energy = 0.511unit

Mass of  ,, ,, 1 unit ,, ,,,,,,,,,,,,,,,,,,,,,,,,=0.511/9.1 =.0.0567

1 energy X “L”= 1.24 x 0.413334= 0.51253 or 0.51253/ 0.0567 =9.04 unit (Mass)

1 charge X energy X ‘’L’’ = 1.602 x 13.6 =21.787 or     21.787/0.413334=9 unit (One unit mass)

Or ,1 constant X 7 = 1.2919 x 7=9.04(one unit mass.)

So ,in every aspect 9 unit mass is present.

*#* By ensuring that calculation we get the new rules---

(A) 1.2919 x 0.413334=0.534 unt“H” atom’s 1^st cell radius.

(B)  1.602 / 0.413334= 3.875 Visible light’s Red frequency .

(C)  1.602 x 0.413334 =0.6621 x 10 =Almost Plank’s constant.

   (1.6028 x 0.413334= 0.6625 x 10 =6.625 )

(D)  0.413334x4=1.6533 mass unit (1 proton is heavier than 1 electron then , 1837  (=1837 X 9 = 16533)  so, if we calculate by dividing it with 10000 Then ,we get the used unit

(E) 1 stagnant electron’s mass =9.1 unit we get -,,9.1/7=1.299 or 1.299/0.413334=3.1427=π (one pi )

(F) 1.602 X 13.6 =21.787/7 = 3.11 ,,3.11X0.413334=1.285 (energy)  and 9/7 = 1.285.(mass

 (G) Relation with the Pythagoras Theory -- Pythagoras Formula – a^2 + b^2 = c^2

                    Charge^2 + L^2 = Mass^2 (or Weight ^2)

(Newtron’s Mass= 9 X 1839= 16551,unit /10000=1.6551)               

  Or-- 1.602^2 + 0.413334 ^2= 1.6551^2

Or--  2.566404 + 0.170845 = 2.73937  Or--   2.7373249 = 2.74    Or--  2.74 = 2.74 (PROVED)

Which is the actual relation between  Pythagoras main and ancient  rules.

[nb.>No part of this publication may be reproduced or any form or any means or any information,  without permission from the Author or chief in charge ]

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